Aggressive Wheels & Stretched Tires: Post 'Em Up! [[Some NSFW]]
generally its 1 degree of camber= 5mm of space but that of course gets blurred when you introduce the fender work which by doing a little more of can prevent having to add more neg camber to a certain extent
but yes 1 degree of camber=5mm of space
but you don't really go by that, it's not sooo technical, once the car is getting its alignment you go by sight
but yes 1 degree of camber=5mm of space
but you don't really go by that, it's not sooo technical, once the car is getting its alignment you go by sight
generally its 1 degree of camber= 5mm of space but that of course gets blurred when you introduce the fender work which by doing a little more of can prevent having to add more neg camber to a certain extent
but yes 1 degree of camber=5mm of space
but you don't really go by that, it's not sooo technical, once the car is getting its alignment you go by sight
but yes 1 degree of camber=5mm of space
but you don't really go by that, it's not sooo technical, once the car is getting its alignment you go by sight
Helping a friend out with his setup, looking for a definitive answer on this and I'm sure one of your guys can confirm.
X mm = 1 degree of camber
What is X? I've read 5mm all the way up to 10mm. If you go 5mm more agressive how much camber do you need to add so everything clears?
This is for 19s by the way.
Thanks guys!
X mm = 1 degree of camber
What is X? I've read 5mm all the way up to 10mm. If you go 5mm more agressive how much camber do you need to add so everything clears?
This is for 19s by the way.
Thanks guys!
In this pic, visualize your wheel well. The angle is front the center point of your wheel. The angle (theta) will be the degree change in your camber setting. Side CB (adjacent side) will be your wheel + tire height. Side AB will be your clearance (opposite side)
remember: tan(angle theta) = opposite side(AB)/adjacent side(CB)
therefore: to figure out opposite side length (AB) you must have the following algabraic formula:
tan(angle theta) x adjacent side (CB) = opposite side (AB)
tan(theta)xCB = AB
theta = tan(1*) = .0175
CB = Sidewall height (mm) + (Wheel diameter in mm/2) {note 1in = 25.4mm)
AB = clearance (mm)
theta(CB) = AB
Here is what I ran for my car today. Running a 255/35/19 rear
Sidewall height = 255(.35) = 89.25mm
Wheel Diameter = 19"(25.4) = 482.6mm/2 = 241.3mm (radius)
CB = 89.25+241.3 = 330.5mm
.0175(330.55) = 5.78mm overall change in clearance from the fender line w/ a 1* change in camber (+ or -)
Last edited by Matzo Ball; 11-08-2010 at 11:01 PM.