Drivetrain Questions and info regarding transmissions, clutches, etc.

Drivetrain Parasitic Loss

Thread Tools
 
Search this Thread
 
Rate Thread
 
Old Mar 20, 2006 | 10:06 AM
  #16  
Q45tech's Avatar
Registered User
Joined: Dec 2003
Posts: 2,514
Likes: 5
From: Marietta, Georgia
Just to make you guys feel better. Take a look at these chassis dyno numbers from a cross section of old and newish Pontiac muscle cars:

They speak of how tire size, diff ratio affects the outcome on dyno.
Look at thoses monster peak torques and relatively low HP for such big engines [ 389, 400, & 455] compared to a modern 346. Remember your engine is 214 cubic inches.

http://www.highperformancepontiac.co...407pon_engine/
 
Reply
Old Mar 20, 2006 | 10:29 AM
  #17  
trey.hutcheson's Avatar
Staff Alumni
Staff Alumni
iTrader: (2)
Joined: Apr 2005
Posts: 3,521
Likes: 2
From: Birmingham AL
The problem with deriving a drivetrain loss percentage is that it's a moving target. One must take absolute endpoints to calculate the loss. We have one absolute endpoint, the published crank numbers, and the other endpoint, rear-wheel horsepower, is not so absolute. I'm preaching to the choir here, but every dyno we see posted is different, and comparisons amongst dynos should not be made lightly. Then one has the method MechEE describes.

For what it's worth, Doug Stewart, from Crawford, claims a 17% loss for manuals when comparing against his local dynojet numbers.

And I agree with Pasta that the numbers cannot be inflated. Our cars exhibit a relatively flat torque curve, and is a loss in the neighborhood of 25% or greater were in fact accurate, people would not be hitting 13's at over 100mph stock, especially in a 3500 pound car.
 
Reply
Old Mar 20, 2006 | 12:21 PM
  #18  
Q45tech's Avatar
Registered User
Joined: Dec 2003
Posts: 2,514
Likes: 5
From: Marietta, Georgia
http://swri.edu/4org/d03/vehsys/pres...ainTesting.pdf

Interesting graphs in middle for different components.

Simple to measure power losses by measuring the temperature rise of each component STEADY STATE LOSSES..........however more complicated in a short time of acceleration.

Things like torque convertors have variable losses depending on the speed difference input to output vs steady state of say 12-3-14% or 3% in lockup mode. They are also speed sensitive based on churning of ATF and amount of air bubbles created and absorbed by ATF. Same with the tranny pump efficiency it is speed sensitive over the 2,000- 7,000 rpm input range.

http://www.kennebell.net/techinfo/ge...tVariables.pdf
 
Reply
Old Mar 20, 2006 | 12:49 PM
  #19  
OC 350GTCoupe's Avatar
Registered User
Joined: Feb 2006
Posts: 201
Likes: 0
Im sure many stock automatic G's have dynoed over 224 RWHP. 280BHP - 20% drivetrain loss for an automatic is only 224 RWHP.
 
Reply
Old Mar 20, 2006 | 01:16 PM
  #20  
JC79G35's Avatar
Registered User
iTrader: (6)
Joined: Apr 2005
Posts: 297
Likes: 0
From: Chicago IL
I do wish I dyno'd my G stock.

I took the average of 220 WHP into account when I took my car to the dyno over last summer. It was 93 degrees, on a dynojet with the following mods: AEM CAI and Stillen dual exhaust. I got 231 WHP, so the mods gave me 11 WHP??! Now that I think about it, it might seem a bit high. Then 2 weeks ago I got the car dyno'd on a Mustang dyno with the same mods (in addition to Craford plenum/cats and IMR grounding kit) and got 238 WHP. So, that's a 7 WHP gain. If I believe the Mustang that is. Perhaps I should take the car back to the dynojet place and get it dyno'd there again in "non-Sahara" conditions.
 
Reply
Old Mar 20, 2006 | 02:10 PM
  #21  
DaveB's Avatar
Registered User
iTrader: (9)
Joined: Aug 2003
Posts: 6,573
Likes: 72
From: Kansas City
FYI, you don't multiply the numbers times 1.X (X being the assumed % loss). The correct way to calculate the loss is divide the whp by 1-assumed % loss.

I think it's very safe to assume a 20% loss for an auto and around 17% for the 6MT. So here's the formula:

Auto making 231whp = 231/.8 = 289hp

6MT making 231whp = 231/.83 = 278hp
 
Reply
Old Mar 20, 2006 | 05:18 PM
  #22  
Q45tech's Avatar
Registered User
Joined: Dec 2003
Posts: 2,514
Likes: 5
From: Marietta, Georgia
There is no single accurate number [accurate to 1% or even 2%] for losses it varies as you change rpm.

Losses at 4,000 will be less than losses at 6500. Losses will change during the dyno run as the [diff and tranny] lubricants heat up and as the tires change temperature.

This is in addition to the probable power losses from the engine as it heats up why back to back runs vary.
 
Reply
Old Mar 20, 2006 | 06:59 PM
  #23  
MechEE's Avatar
Registered User
iTrader: (3)
Joined: Dec 2005
Posts: 1,214
Likes: 0
From: San Francisco
Originally Posted by trey.hutcheson
The problem with deriving a drivetrain loss percentage is that it's a moving target. One must take absolute endpoints to calculate the loss. We have one absolute endpoint, the published crank numbers, and the other endpoint, rear-wheel horsepower, is not so absolute. I'm preaching to the choir here, but every dyno we see posted is different, and comparisons amongst dynos should not be made lightly. Then one has the method MechEE describes.

For what it's worth, Doug Stewart, from Crawford, claims a 17% loss for manuals when comparing against his local dynojet numbers.

And I agree with Pasta that the numbers cannot be inflated. Our cars exhibit a relatively flat torque curve, and is a loss in the neighborhood of 25% or greater were in fact accurate, people would not be hitting 13's at over 100mph stock, especially in a 3500 pound car.
Again, it's hard to dispute the fact that I can measure quite accurately instantaneous acceleration and speed, which gives me power directly with the weight of the car.

What would be interesting is to simulate some 1/4 mile accelerations with a stock power curve, and scale it until you get trap speed numbers similar to what people are getting stock. This will give you a rough idea of how much power they are putting down, and would be pretty easy to simulate. Since I have high-resolution data from my dyno, I'll use mine, and scale it up or down to get various trap speeds.
 
Reply
Old Mar 20, 2006 | 07:05 PM
  #24  
shunra's Avatar
Registered User
Joined: May 2005
Posts: 68
Likes: 0
Originally Posted by thx007
But...

"...if we agree that stock cars chassis dyno at 210-220, well 215 x 1.2 = 258 flywheel hp, a far cry from what Infiniti says (280 or 298)."

So 215 x 1.22 still only gives you 262. Perhaps a better question would be, was there a noticeable chassis dyno difference between the 03-04 cars and the 05's?

If a 298hp rated 6MT dyno's at 230rwhp, that's a huge 29.6% loss. I can't believe we are losing that much.
You are doing the math wrong. It is making it look worse than it really is.

The 22% loss applies to the HP at the crank not the HP at the wheels. So for a 22% loss the math should be like this:

For a 280hp (crank) motor 280 * 0.78 = 218.4 hp at the wheels
For a 298hp (crank) motor 298 * 0.78 = 232.44 hp at the wheels

From your exaple above of a 298hp engine with a dyno of 230 - that would convert to a 22.8% drivetrain loss (not 29.6)

An easier way to think of it is like this. If a motor makes 280hp but looses 22% of it to drivetrain it will lose 280 * 0.22 = 61.6hp. So if it looses 61.6 hp in the drivetrain you would expect the car to put down 280 - 61.6 = 218.4hp at the wheels.
 
Reply
Old Mar 20, 2006 | 09:48 PM
  #25  
thx007's Avatar
Thread Starter
|
Registered User
Joined: Dec 2005
Posts: 20
Likes: 0
Ok, I see the math error. Doing it a bit backwards eh? Blimey bugger I am. Well, I still don't like it. Seems like the drivetrain should still be more efficient than that. It still makes it similiar to a heavy truck drivetrain in amount of loss.

I WANT MORE POWER TO THE GROUND!!!
 
Reply
Old Mar 20, 2006 | 11:52 PM
  #26  
trey.hutcheson's Avatar
Staff Alumni
Staff Alumni
iTrader: (2)
Joined: Apr 2005
Posts: 3,521
Likes: 2
From: Birmingham AL
Originally Posted by thx007
I WANT MORE POWER TO THE GROUND!!!
That auto tranny ain't helping there...

<< where's that poking dude with a stick smiley? >>
 
Reply
Old Mar 20, 2006 | 11:52 PM
  #27  
trey.hutcheson's Avatar
Staff Alumni
Staff Alumni
iTrader: (2)
Joined: Apr 2005
Posts: 3,521
Likes: 2
From: Birmingham AL
Originally Posted by MechEE
Again, it's hard to dispute the fact that I can measure quite accurately instantaneous acceleration and speed, which gives me power directly with the weight of the car.

What would be interesting is to simulate some 1/4 mile accelerations with a stock power curve, and scale it until you get trap speed numbers similar to what people are getting stock. This will give you a rough idea of how much power they are putting down, and would be pretty easy to simulate. Since I have high-resolution data from my dyno, I'll use mine, and scale it up or down to get various trap speeds.
When you do this, I'd like to see the calculated hp/tq numbers plotted by rpm like on a dyno chart for comparison's sake.
 
Reply
Old Mar 21, 2006 | 12:10 AM
  #28  
thx007's Avatar
Thread Starter
|
Registered User
Joined: Dec 2005
Posts: 20
Likes: 0
Originally Posted by trey.hutcheson
That auto tranny ain't helping there...
Granted, but a serious 15 hours a week in stop n' go wouldn't help a bad left knee either.

Besides, we're catching up. The new 6AT C6 is only .2 off the 6MT version. Ok, ok... granted I don't have a lightweight, transaxle mounted, paddle-shifting tranny. But give me time!!
 
Reply
Old Mar 21, 2006 | 11:37 AM
  #29  
shunra's Avatar
Registered User
Joined: May 2005
Posts: 68
Likes: 0
Originally Posted by thx007
Seems like the drivetrain should still be more efficient than that.
Yea I agree with you there.
 
Reply
Old Mar 21, 2006 | 11:23 PM
  #30  
DaveB's Avatar
Registered User
iTrader: (9)
Joined: Aug 2003
Posts: 6,573
Likes: 72
From: Kansas City
Originally Posted by thx007
Seems like the drivetrain should still be more efficient than that. It still makes it similiar to a heavy truck drivetrain in amount of loss.

I WANT MORE POWER TO THE GROUND!!!
I wouldn't get too caught up in the peak numbers. These cars are quite strong for having rather small V6s. My sedan with just a Z pipe matched the 1/4 mile times and MPHs of my 250whp/270wtq 94 Z28 (stock). Both cars weighed the same yet the VQ35 is matching the acceleration of a 5.7 liter V8. Granted it only took about $1500 in mods to get my Z into the mid 13s, but that car was severely choked from the factory so that it wouldn't outrun the Vette of the same year. Regardless, the VQ35 accelerates the G35 harder than you'd think mostly because the powerband is very fat and the stock 5AT/6MT gearing is damn near ideal.

As for drivetrain losses, consider some things. These cars have a big and heavy driveshaft to keep the drivetrain extremely smooth. The driveshaft has to spin two axles to move the car. These cars also have rather heavy rims and beefy (heavy) brakes. It all adds up. A FWD car with the same motor will see around 10whp more simply because it doesn't have a driveshaft.
 
Reply


You have already rated this thread Rating: Thread Rating: 0 votes,  average.


All times are GMT -4. The time now is 11:34 AM.