Another NOOB question =(
#1
Another NOOB question =(
I purchased my used 2005 G35 Coupe (Automatic) about a couple of months ago and I'm loving the vehicle. This purchased was made in the Sacramento, CA area and I reside in Reno, NV near Lake Tahoe. When I bought this car and whenever I'm in California, this car performs like a champ...very spirited. However, when I'm back in my hometown of Reno (located in the mountains), the car feels somewhat sluggish. I understand that when I'm in the Bay area or southern Cali, the altitude allows the car to breathe better...in turn it performs better. Is there anything I can do to get the car to breathe better in the upper elevations (4000 ft. elevation)?
Do I need to get something flashed or reprogrammed to make the computer think that its at a lower elevation? If so, can someone point me in the direction to get this done? I want my car to feel the same it does in lower elevations.
Thanks for all your help.
Do I need to get something flashed or reprogrammed to make the computer think that its at a lower elevation? If so, can someone point me in the direction to get this done? I want my car to feel the same it does in lower elevations.
Thanks for all your help.
#3
Up in the mountains the air molecules are spaced the same amount just there is less air pressure at sea level the air pressure is 14.7psi. While the computer should compensate for this it will not add the performance you will be looking for it will just make the engine run safer so nothing will happen to it. I am not sure what your setup is but if you have a stock intake run a cold air intake. A cold air intake will keep the heat from your engine away from the air, and in doing so it will make the air molecules closer together so you can pair up more parts of fuel to parts of air. That is just something you can do. PM me if you want and we can go over it a little more.
Last edited by 88G35; 01-25-2008 at 04:01 PM.
#4
Originally Posted by 88G35
Up in the mountains the air molecules are spaced the same amount just there is less air pressure at sea level the air pressure is 14.7psi.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
#6
Originally Posted by CalgaryG
That's not correct... taking the composition of air to be constant as you increase altitude (not entirely precise, as the ratio of O2 molecules to Oradical species decreases, but close enough for our purposes), the mole fraction of oxygen is equal as you increase altitude. Therefore as atmospheric pressure decreases from 14.7 psi, the partial pressure of oxygen also decreases.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
#7
Originally Posted by CalgaryG
That's not correct... taking the composition of air to be constant as you increase altitude (not entirely precise, as the ratio of O2 molecules to Oradical species decreases, but close enough for our purposes), the mole fraction of oxygen is equal as you increase altitude. Therefore as atmospheric pressure decreases from 14.7 psi, the partial pressure of oxygen also decreases.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Thanks everyone! So in reality there's nothing I can do to compensate for the altitude and how my car performs? LOL...I need to move to sea level.
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#8
Originally Posted by CalgaryG
That's not correct... taking the composition of air to be constant as you increase altitude (not entirely precise, as the ratio of O2 molecules to Oradical species decreases, but close enough for our purposes), the mole fraction of oxygen is equal as you increase altitude. Therefore as atmospheric pressure decreases from 14.7 psi, the partial pressure of oxygen also decreases.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
See? We can learn about a lot more than just cars here on G35driver.com!
#9
Originally Posted by ovrkast
Thanks everyone! So in reality there's nothing I can do to compensate for the altitude and how my car performs? LOL...I need to move to sea level.
Oh, and forced induction would certainly solve that "sluggish" feeling!
Or a 75 shot of Nitrous Oxide...
#11
Originally Posted by CalgaryG
That's not correct... taking the composition of air to be constant as you increase altitude (not entirely precise, as the ratio of O2 molecules to Oradical species decreases, but close enough for our purposes), the mole fraction of oxygen is equal as you increase altitude. Therefore as atmospheric pressure decreases from 14.7 psi, the partial pressure of oxygen also decreases.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
NERD ALERT! NERD ALERT!!
jk I'm a biology major
#13
Originally Posted by CalgaryG
That's not correct... taking the composition of air to be constant as you increase altitude (not entirely precise, as the ratio of O2 molecules to Oradical species decreases, but close enough for our purposes), the mole fraction of oxygen is equal as you increase altitude. Therefore as atmospheric pressure decreases from 14.7 psi, the partial pressure of oxygen also decreases.
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
Looking at the ideal gas law, PV=nRT --> V= nRT / P, the equivalent volume of oxygen must increase as its partial pressure decreases as n, R and T are constant. Therefore the O2 molecules are actually spaced further apart!
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